Decodes the "multipart/form-data" request in msg
; this is a convenience method for the case when you have a single file
upload control in a form.
(Or when you don't have any file upload controls, but are still using "multipart/form-data" anyway.) Pass the name of the file upload
control in file_control_name
, and decode_multipart will extract the uploaded file data into
filename
, content_type
, and file
. All of the other form control data will be returned (as strings,
as with decode) in the returned GenericSet.
You may pass null
for filename
, content_type
and/or file
if you do not care about
those fields. decode_multipart may also return null
in those fields if the client did not provide
that information. You must free the returned filename and content-type with g_free, and the returned file data
with free.
If you have a form with more than one file upload control, you will need to decode it manually, using Multipart.from_message and get_part.
msg |
a Message containing a "multipart/form-data" request body |
file_control_name |
the name of the HTML file upload control, or |
filename |
return location for the name of the uploaded file, or |
content_type |
return location for the MIME type of the uploaded file, or |
file |
return location for the uploaded file data, or |
a hash table containing the name/value pairs (other than |